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Remove UseGcc makefile var
[ghc-hetmet.git]
/
mk
/
config.mk.in
diff --git
a/mk/config.mk.in
b/mk/config.mk.in
index
be8b57b
..
4d93905
100644
(file)
--- a/
mk/config.mk.in
+++ b/
mk/config.mk.in
@@
-540,18
+540,10
@@
endif
# the flag --with-gcc=<blah> instead. The reason is that the configure script
# needs to know which gcc you're using in order to perform its tests.
# the flag --with-gcc=<blah> instead. The reason is that the configure script
# needs to know which gcc you're using in order to perform its tests.
-HaveGcc = @HaveGcc@
-UseGcc = YES
WhatGccIsCalled = @WhatGccIsCalled@
GccVersion = @GccVersion@
WhatGccIsCalled = @WhatGccIsCalled@
GccVersion = @GccVersion@
-GccLT34 = @GccLT34@
-ifeq "$(strip $(HaveGcc))" "YES"
-ifneq "$(strip $(UseGcc))" "YES"
- CC = cc
-else
- CC = $(WhatGccIsCalled)
-endif
-endif
+GccLT34 = @GccLT34@
+CC = $(WhatGccIsCalled)
# C compiler and linker flags from configure (e.g. -m<blah> to select
# correct C compiler backend). The stage number is the stage of GHC
# C compiler and linker flags from configure (e.g. -m<blah> to select
# correct C compiler backend). The stage number is the stage of GHC