- /** perform the reduction */
- public void go() {
- if (done) return;
- done = true;
- pendingReduct.remove(this);
- pendingReductions--;
-
- if (r==null) {
- for(Parser.Table.Reduction r : token==null ? n.state.getEofReductions() : n.state.getReductions(token)) {
-
- // UGLY HACK
- // The problem here is that a "reduction of length 1"
- // performed twice with different values of n2 needs
- // to only create a *single* new result, but must add
- // multiple parents to the node holding that result.
- // The current reducer doesn't differentiate between
- // the next node of an n-pop reduction and the
- // ultimate parent of the last pop, so we need to
- // cache instances here as a way of avoiding
- // recreating them.
-
- // currently we have this weird problem where we
- // have to do an individual reduct for each child
- // when the reduction length is one (ie the
- // children wind up being children of the newly
- // created node rather than part of the popped
- // sequence
-
- if (r.numPop == 1) {
- Forest ret = n.cache().get(r);
- if (ret != null) r.reduce(n, n2, n.phase, ret);
- else n.cache().put(r, r.reduce(n, n2, n.phase, null));
- }
- }
- for(Parser.Table.Reduction r : token==null ? n.state.getEofReductions() : n.state.getReductions(token)) {
- if (r.numPop <= 1) continue;
- r.reduce(n, n2, Phase.this, null);
- }
- } else if (r.numPop != 1) {
- r.reduce(n, n2, Phase.this, null);
- }
- }