+Note [Arguments of let-bound constructors]
+~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+Consider
+ f x = let y = expensive x in
+ let z = (True,y) in
+ (case z of {(p,q)->q}, case z of {(p,q)->q})
+We feel free to duplicate the WHNF (True,y), but that means
+that y may be duplicated thereby.
+
+If we aren't careful we duplicate the (expensive x) call!
+Constructors are rather like lambdas in this way.
+