[project @ 2002-02-14 15:03:38 by simonpj]

[project @ 2002-02-14 15:03:38 by simonpj]
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	Desugar existential matches correctly
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Consider
	data T = forall a. Ord a => T a (a->Int)

	f (T x f) True  = ...expr1...
	f (T y g) False = ...expr2..

When we put in the tyvars etc we get

	f (T a (d::Ord a) (x::a) (f::a->Int)) True =  ...expr1...
	f (T b (e::Ord a) (y::a) (g::a->Int)) True =  ...expr2...

After desugaring etc we'll get a single case:

	f = \t::T b::Bool ->
	    case t of
	       T a (d::Ord a) (x::a) (f::a->Int)) ->
	    case b of
		True  -> ...expr1...
		False -> ...expr2...

*** We have to substitute [a/b, d/e] in expr2! **

Originally I tried to use
	(\b -> let e = d in expr2) a
to do this substitution.  While this is "correct" in a way, it fails
Lint, because e::Ord b but d::Ord a.

So now I simply do the substitution properly using substExpr.