--- /dev/null
+// RTree.java
+// Java Spatial Index Library
+// Copyright (C) 2002 Infomatiq Limited
+//
+// This library is free software; you can redistribute it and/or
+// modify it under the terms of the GNU Lesser General Public
+// License as published by the Free Software Foundation; either
+// version 2.1 of the License, or (at your option) any later version.
+//
+// This library is distributed in the hope that it will be useful,
+// but WITHOUT ANY WARRANTY; without even the implied warranty of
+// MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
+// Lesser General Public License for more details.
+//
+// You should have received a copy of the GNU Lesser General Public
+// License along with this library; if not, write to the Free Software
+// Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
+
+package com.infomatiq.jsi.rtree;
+
+import gnu.trove.TIntArrayList;
+import gnu.trove.TIntObjectHashMap;
+import gnu.trove.TIntProcedure;
+import gnu.trove.TIntStack;
+import java.util.Properties;
+
+import com.infomatiq.jsi.IntProcedure;
+import com.infomatiq.jsi.Point;
+import com.infomatiq.jsi.Rectangle;
+import com.infomatiq.jsi.SpatialIndex;
+
+/**
+ * <p>This is a lightweight RTree implementation, specifically designed
+ * for the following features (in order of importance):
+ * <ul>
+ * <li>Fast intersection query performance. To achieve this, the RTree
+ * uses only main memory to store entries. Obviously this will only improve
+ * performance if there is enough physical memory to avoid paging.</li>
+ * <li>Low memory requirements.</li>
+ * <li>Fast add performance.</li>
+ * </ul></p>
+ *
+ * <p>The main reason for the high speed of this RTree implementation is the
+ * avoidance of the creation of unnecessary objects, mainly achieved by using
+ * primitive collections from the trove4j library.</p>
+ *
+ * @author aled.morris@infomatiq.co.uk
+ * @version 1.0b2
+ */
+public class RTree implements SpatialIndex {
+
+ private static final String version = "1.0b2";
+
+ // parameters of the tree
+ private final static int DEFAULT_MAX_NODE_ENTRIES = 10;
+ int maxNodeEntries;
+ int minNodeEntries;
+
+ // map of nodeId -> node object
+ // [x] TODO eliminate this map - it should not be needed. Nodes
+ // can be found by traversing the tree.
+ private TIntObjectHashMap nodeMap = new TIntObjectHashMap();
+
+ // internal consistency checking - set to true if debugging tree corruption
+ private final static boolean INTERNAL_CONSISTENCY_CHECKING = false;
+
+ // used to mark the status of entries during a node split
+ private final static int ENTRY_STATUS_ASSIGNED = 0;
+ private final static int ENTRY_STATUS_UNASSIGNED = 1;
+ private byte[] entryStatus = null;
+ private byte[] initialEntryStatus = null;
+
+ // stacks used to store nodeId and entry index of each node
+ // from the root down to the leaf. Enables fast lookup
+ // of nodes when a split is propagated up the tree.
+ private TIntStack parents = new TIntStack();
+ private TIntStack parentsEntry = new TIntStack();
+
+ // initialisation
+ private int treeHeight = 1; // leaves are always level 1
+ private int rootNodeId = 0;
+ private int size = 0;
+
+ // Enables creation of new nodes
+ private int highestUsedNodeId = rootNodeId;
+
+ // Deleted node objects are retained in the nodeMap,
+ // so that they can be reused. Store the IDs of nodes
+ // which can be reused.
+ private TIntStack deletedNodeIds = new TIntStack();
+
+ // List of nearest rectangles. Use a member variable to
+ // avoid recreating the object each time nearest() is called.
+ private TIntArrayList nearestIds = new TIntArrayList();
+
+ // Inner class used as a bridge between the trove4j TIntProcedure
+ // and the SpatialIndex IntProcedure. This is used because
+ // the nearest rectangles must be stored as they are found, in
+ // case a closer one is found later.
+ //
+ // A single instance of this class is used to avoid creating a new
+ // one every time nearest() is called.
+ private class TIntProcedureVisit implements TIntProcedure {
+ public IntProcedure m_intProcedure = null;
+
+ public void setProcedure(IntProcedure ip) {
+ m_intProcedure = ip;
+ }
+ public boolean execute(int i) {
+ m_intProcedure.execute(i);
+ return true;
+ }
+ };
+ private TIntProcedureVisit visitProc = new TIntProcedureVisit();
+
+ /**
+ * Constructor. Use init() method to initialize parameters of the RTree.
+ */
+ public RTree() {
+ return; // NOP
+ }
+
+ //-------------------------------------------------------------------------
+ // public implementation of SpatialIndex interface:
+ // init(Properties)
+ // add(Rectangle, int)
+ // delete(Rectangle, int)
+ // nearest(Point, IntProcedure, float)
+ // intersects(Rectangle, IntProcedure)
+ // contains(Rectangle, IntProcedure)
+ // size()
+ //-------------------------------------------------------------------------
+ /**
+ * <p>Initialize implementation dependent properties of the RTree.
+ * Currently implemented properties are:
+ * <ul>
+ * <li>MaxNodeEntries</li> This specifies the maximum number of entries
+ * in a node. The default value is 10, which is used if the property is
+ * not specified, or is less than 2.
+ * <li>MinNodeEntries</li> This specifies the minimum number of entries
+ * in a node. The default value is half of the MaxNodeEntries value (rounded
+ * down), which is used if the property is not specified or is less than 1.
+ * </ul></p>
+ *
+ * @see com.infomatiq.jsi.SpatialIndex#init(Properties)
+ */
+ public void init(Properties props) {
+ maxNodeEntries = Integer.parseInt(props.getProperty("MaxNodeEntries", "0"));
+ minNodeEntries = Integer.parseInt(props.getProperty("MinNodeEntries", "0"));
+
+ // Obviously a node with less than 2 entries cannot be split.
+ // The node splitting algorithm will work with only 2 entries
+ // per node, but will be inefficient.
+ if (maxNodeEntries < 2) {
+ System.err.println("Invalid MaxNodeEntries = " + maxNodeEntries + " Resetting to default value of " + DEFAULT_MAX_NODE_ENTRIES);
+ maxNodeEntries = DEFAULT_MAX_NODE_ENTRIES;
+ }
+
+ // The MinNodeEntries must be less than or equal to (int) (MaxNodeEntries / 2)
+ if (minNodeEntries < 1 || minNodeEntries > maxNodeEntries / 2) {
+ System.err.println("MinNodeEntries must be between 1 and MaxNodeEntries / 2");
+ minNodeEntries = maxNodeEntries / 2;
+ }
+
+ entryStatus = new byte[maxNodeEntries];
+ initialEntryStatus = new byte[maxNodeEntries];
+
+ for (int i = 0; i < maxNodeEntries; i++) {
+ initialEntryStatus[i] = ENTRY_STATUS_UNASSIGNED;
+ }
+
+ Node root = new Node(rootNodeId, 1, maxNodeEntries);
+ nodeMap.put(rootNodeId, root);
+
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#add(Rectangle, int)
+ */
+ public void add(Rectangle r, int id) {
+ /*
+ if (log.isDebugEnabled()) {
+ //////log.debug("Adding rectangle " + r + ", id " + id);
+ }
+ */
+ add(r.copy(), id, 1);
+
+ size++;
+ }
+
+ /**
+ * Adds a new entry at a specified level in the tree
+ */
+ private void add(Rectangle r, int id, int level) {
+ // I1 [Find position for new record] Invoke ChooseLeaf to select a
+ // leaf node L in which to place r
+ Node n = chooseNode(r, level);
+ Node newLeaf = null;
+
+ // I2 [Add record to leaf node] If L has room for another entry,
+ // install E. Otherwise invoke SplitNode to obtain L and LL containing
+ // E and all the old entries of L
+ if (n.entryCount < maxNodeEntries) {
+ n.addEntryNoCopy(r, id);
+ } else {
+ newLeaf = splitNode(n, r, id);
+ }
+
+ // I3 [Propagate changes upwards] Invoke AdjustTree on L, also passing LL
+ // if a split was performed
+ Node newNode = adjustTree(n, newLeaf);
+
+ // I4 [Grow tree taller] If node split propagation caused the root to
+ // split, create a new root whose children are the two resulting nodes.
+ if (newNode != null) {
+ int oldRootNodeId = rootNodeId;
+ Node oldRoot = getNode(oldRootNodeId);
+
+ rootNodeId = getNextNodeId();
+ treeHeight++;
+ Node root = new Node(rootNodeId, treeHeight, maxNodeEntries);
+ root.addEntry(newNode.mbr, newNode.nodeId);
+ root.addEntry(oldRoot.mbr, oldRoot.nodeId);
+ nodeMap.put(rootNodeId, root);
+ }
+
+ if (INTERNAL_CONSISTENCY_CHECKING) {
+ checkConsistency(rootNodeId, treeHeight, null);
+ }
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#delete(Rectangle, int)
+ */
+ public boolean delete(Rectangle r, int id) {
+ // FindLeaf algorithm inlined here. Note the "official" algorithm
+ // searches all overlapping entries. This seems inefficient to me,
+ // as an entry is only worth searching if it contains (NOT overlaps)
+ // the rectangle we are searching for.
+ //
+ // Also the algorithm has been changed so that it is not recursive.
+
+ // FL1 [Search subtrees] If root is not a leaf, check each entry
+ // to determine if it contains r. For each entry found, invoke
+ // findLeaf on the node pointed to by the entry, until r is found or
+ // all entries have been checked.
+ parents.clear();
+ parents.push(rootNodeId);
+
+ parentsEntry.clear();
+ parentsEntry.push(-1);
+ Node n = null;
+ int foundIndex = -1; // index of entry to be deleted in leaf
+
+ while (foundIndex == -1 && parents.size() > 0) {
+ n = getNode(parents.peek());
+ int startIndex = parentsEntry.peek() + 1;
+
+ if (!n.isLeaf()) {
+ /*
+ //deleteLog.debug("searching node " + n.nodeId + ", from index " + startIndex);
+ */
+ boolean contains = false;
+ for (int i = startIndex; i < n.entryCount; i++) {
+ if (n.entries[i].contains(r)) {
+ parents.push(n.ids[i]);
+ parentsEntry.pop();
+ parentsEntry.push(i); // this becomes the start index when the child has been searched
+ parentsEntry.push(-1);
+ contains = true;
+ break; // ie go to next iteration of while()
+ }
+ }
+ if (contains) {
+ continue;
+ }
+ } else {
+ foundIndex = n.findEntry(r, id);
+ }
+
+ parents.pop();
+ parentsEntry.pop();
+ } // while not found
+
+ if (foundIndex != -1) {
+ n.deleteEntry(foundIndex, minNodeEntries);
+ condenseTree(n);
+ size--;
+ }
+
+ return (foundIndex != -1);
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#nearest(Point, IntProcedure, float)
+ */
+ public void nearest(Point p, IntProcedure v, float furthestDistance) {
+ Node rootNode = getNode(rootNodeId);
+
+ nearest(p, rootNode, furthestDistance);
+
+ visitProc.setProcedure(v);
+ nearestIds.forEach(visitProc);
+ nearestIds.clear();
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#intersects(Rectangle, IntProcedure)
+ */
+ public void intersects(Rectangle r, IntProcedure v) {
+ Node rootNode = getNode(rootNodeId);
+ intersects(r, v, rootNode);
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#contains(Rectangle, IntProcedure)
+ */
+ public void contains(Rectangle r, IntProcedure v) {
+ // find all rectangles in the tree that are contained by the passed rectangle
+ // written to be non-recursive (should model other searches on this?)
+
+ parents.clear();
+ parents.push(rootNodeId);
+
+ parentsEntry.clear();
+ parentsEntry.push(-1);
+
+ // TODO: possible shortcut here - could test for intersection with the
+ // MBR of the root node. If no intersection, return immediately.
+
+ while (parents.size() > 0) {
+ Node n = getNode(parents.peek());
+ int startIndex = parentsEntry.peek() + 1;
+
+ if (!n.isLeaf()) {
+ // go through every entry in the index node to check
+ // if it intersects the passed rectangle. If so, it
+ // could contain entries that are contained.
+ boolean intersects = false;
+ for (int i = startIndex; i < n.entryCount; i++) {
+ if (r.intersects(n.entries[i])) {
+ parents.push(n.ids[i]);
+ parentsEntry.pop();
+ parentsEntry.push(i); // this becomes the start index when the child has been searched
+ parentsEntry.push(-1);
+ intersects = true;
+ break; // ie go to next iteration of while()
+ }
+ }
+ if (intersects) {
+ continue;
+ }
+ } else {
+ // go through every entry in the leaf to check if
+ // it is contained by the passed rectangle
+ for (int i = 0; i < n.entryCount; i++) {
+ if (r.contains(n.entries[i])) {
+ v.execute(n.ids[i]);
+ }
+ }
+ }
+ parents.pop();
+ parentsEntry.pop();
+ }
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#size()
+ */
+ public int size() {
+ return size;
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#getBounds()
+ */
+ public Rectangle getBounds() {
+ Rectangle bounds = null;
+
+ Node n = getNode(getRootNodeId());
+ if (n != null && n.getMBR() != null) {
+ bounds = n.getMBR().copy();
+ }
+ return bounds;
+ }
+
+ /**
+ * @see com.infomatiq.jsi.SpatialIndex#getVersion()
+ */
+ public String getVersion() {
+ return "RTree-" + version;
+ }
+ //-------------------------------------------------------------------------
+ // end of SpatialIndex methods
+ //-------------------------------------------------------------------------
+
+ /**
+ * Get the next available node ID. Reuse deleted node IDs if
+ * possible
+ */
+ private int getNextNodeId() {
+ int nextNodeId = 0;
+ if (deletedNodeIds.size() > 0) {
+ nextNodeId = deletedNodeIds.pop();
+ } else {
+ nextNodeId = 1 + highestUsedNodeId++;
+ }
+ return nextNodeId;
+ }
+
+ /**
+ * Get a node object, given the ID of the node.
+ */
+ public Node getNode(int index) {
+ return (Node) nodeMap.get(index);
+ }
+
+ /**
+ * Get the highest used node ID
+ */
+ public int getHighestUsedNodeId() {
+ return highestUsedNodeId;
+ }
+
+ /**
+ * Get the root node ID
+ */
+ public int getRootNodeId() {
+ return rootNodeId;
+ }
+
+ /**
+ * Split a node. Algorithm is taken pretty much verbatim from
+ * Guttman's original paper.
+ *
+ * @return new node object.
+ */
+ private Node splitNode(Node n, Rectangle newRect, int newId) {
+ // [Pick first entry for each group] Apply algorithm pickSeeds to
+ // choose two entries to be the first elements of the groups. Assign
+ // each to a group.
+
+ // debug code
+ float initialArea = 0;
+ /*
+ if (log.isDebugEnabled()) {
+ Rectangle union = n.mbr.union(newRect);
+ initialArea = union.area();
+ }
+ */
+ System.arraycopy(initialEntryStatus, 0, entryStatus, 0, maxNodeEntries);
+
+ Node newNode = null;
+ newNode = new Node(getNextNodeId(), n.level, maxNodeEntries);
+ nodeMap.put(newNode.nodeId, newNode);
+
+ pickSeeds(n, newRect, newId, newNode); // this also sets the entryCount to 1
+
+ // [Check if done] If all entries have been assigned, stop. If one
+ // group has so few entries that all the rest must be assigned to it in
+ // order for it to have the minimum number m, assign them and stop.
+ while (n.entryCount + newNode.entryCount < maxNodeEntries + 1) {
+ if (maxNodeEntries + 1 - newNode.entryCount == minNodeEntries) {
+ // assign all remaining entries to original node
+ for (int i = 0; i < maxNodeEntries; i++) {
+ if (entryStatus[i] == ENTRY_STATUS_UNASSIGNED) {
+ entryStatus[i] = ENTRY_STATUS_ASSIGNED;
+ n.mbr.add(n.entries[i]);
+ n.entryCount++;
+ }
+ }
+ break;
+ }
+ if (maxNodeEntries + 1 - n.entryCount == minNodeEntries) {
+ // assign all remaining entries to new node
+ for (int i = 0; i < maxNodeEntries; i++) {
+ if (entryStatus[i] == ENTRY_STATUS_UNASSIGNED) {
+ entryStatus[i] = ENTRY_STATUS_ASSIGNED;
+ newNode.addEntryNoCopy(n.entries[i], n.ids[i]);
+ n.entries[i] = null;
+ }
+ }
+ break;
+ }
+
+ // [Select entry to assign] Invoke algorithm pickNext to choose the
+ // next entry to assign. Add it to the group whose covering rectangle
+ // will have to be enlarged least to accommodate it. Resolve ties
+ // by adding the entry to the group with smaller area, then to the
+ // the one with fewer entries, then to either. Repeat from S2
+ pickNext(n, newNode);
+ }
+
+ n.reorganize(this);
+
+ // check that the MBR stored for each node is correct.
+ if (INTERNAL_CONSISTENCY_CHECKING) {
+ if (!n.mbr.equals(calculateMBR(n))) {
+ throw new Error("Error: splitNode old node MBR wrong");
+ }
+
+ if (!newNode.mbr.equals(calculateMBR(newNode))) {
+ throw new Error("Error: splitNode new node MBR wrong");
+ }
+ }
+
+ // debug code
+ /*
+ if (log.isDebugEnabled()) {
+ float newArea = n.mbr.area() + newNode.mbr.area();
+ float percentageIncrease = (100 * (newArea - initialArea)) / initialArea;
+ //log.debug("Node " + n.nodeId + " split. New area increased by " + percentageIncrease + "%");
+ }
+ */
+ return newNode;
+ }
+
+ /**
+ * Pick the seeds used to split a node.
+ * Select two entries to be the first elements of the groups
+ */
+ private void pickSeeds(Node n, Rectangle newRect, int newId, Node newNode) {
+ // Find extreme rectangles along all dimension. Along each dimension,
+ // find the entry whose rectangle has the highest low side, and the one
+ // with the lowest high side. Record the separation.
+ float maxNormalizedSeparation = 0;
+ int highestLowIndex = 0;
+ int lowestHighIndex = 0;
+
+ // for the purposes of picking seeds, take the MBR of the node to include
+ // the new rectangle aswell.
+ n.mbr.add(newRect);
+
+ /*
+ if (log.isDebugEnabled()) {
+ //log.debug("pickSeeds(): NodeId = " + n.nodeId + ", newRect = " + newRect);
+ }
+ */
+
+ for (int d = 0; d < Rectangle.DIMENSIONS; d++) {
+ float tempHighestLow = newRect.min[d];
+ int tempHighestLowIndex = -1; // -1 indicates the new rectangle is the seed
+
+ float tempLowestHigh = newRect.max[d];
+ int tempLowestHighIndex = -1;
+
+ for (int i = 0; i < n.entryCount; i++) {
+ float tempLow = n.entries[i].min[d];
+ if (tempLow >= tempHighestLow) {
+ tempHighestLow = tempLow;
+ tempHighestLowIndex = i;
+ } else { // ensure that the same index cannot be both lowestHigh and highestLow
+ float tempHigh = n.entries[i].max[d];
+ if (tempHigh <= tempLowestHigh) {
+ tempLowestHigh = tempHigh;
+ tempLowestHighIndex = i;
+ }
+ }
+
+ // PS2 [Adjust for shape of the rectangle cluster] Normalize the separations
+ // by dividing by the widths of the entire set along the corresponding
+ // dimension
+ float normalizedSeparation = (tempHighestLow - tempLowestHigh) / (n.mbr.max[d] - n.mbr.min[d]);
+
+ if (normalizedSeparation > 1 || normalizedSeparation < -1) {
+ throw new Error("Invalid normalized separation");
+ }
+
+ /*
+ if (log.isDebugEnabled()) {
+ log.debug("Entry " + i + ", dimension " + d + ": HighestLow = " + tempHighestLow +
+ " (index " + tempHighestLowIndex + ")" + ", LowestHigh = " +
+ tempLowestHigh + " (index " + tempLowestHighIndex + ", NormalizedSeparation = " + normalizedSeparation);
+ }
+ */
+
+ // PS3 [Select the most extreme pair] Choose the pair with the greatest
+ // normalized separation along any dimension.
+ if (normalizedSeparation > maxNormalizedSeparation) {
+ maxNormalizedSeparation = normalizedSeparation;
+ highestLowIndex = tempHighestLowIndex;
+ lowestHighIndex = tempLowestHighIndex;
+ }
+ }
+ }
+
+ // highestLowIndex is the seed for the new node.
+ if (highestLowIndex == -1) {
+ newNode.addEntry(newRect, newId);
+ } else {
+ newNode.addEntryNoCopy(n.entries[highestLowIndex], n.ids[highestLowIndex]);
+ n.entries[highestLowIndex] = null;
+
+ // move the new rectangle into the space vacated by the seed for the new node
+ n.entries[highestLowIndex] = newRect;
+ n.ids[highestLowIndex] = newId;
+ }
+
+ // lowestHighIndex is the seed for the original node.
+ if (lowestHighIndex == -1) {
+ lowestHighIndex = highestLowIndex;
+ }
+
+ entryStatus[lowestHighIndex] = ENTRY_STATUS_ASSIGNED;
+ n.entryCount = 1;
+ n.mbr.set(n.entries[lowestHighIndex].min, n.entries[lowestHighIndex].max);
+ }
+
+ /**
+ * Pick the next entry to be assigned to a group during a node split.
+ *
+ * [Determine cost of putting each entry in each group] For each
+ * entry not yet in a group, calculate the area increase required
+ * in the covering rectangles of each group
+ */
+ private int pickNext(Node n, Node newNode) {
+ float maxDifference = Float.NEGATIVE_INFINITY;
+ int next = 0;
+ int nextGroup = 0;
+
+ maxDifference = Float.NEGATIVE_INFINITY;
+
+ /*
+ if (log.isDebugEnabled()) {
+ //log.debug("pickNext()");
+ }
+ */
+
+ for (int i = 0; i < maxNodeEntries; i++) {
+ if (entryStatus[i] == ENTRY_STATUS_UNASSIGNED) {
+
+ if (n.entries[i] == null) {
+ throw new Error("Error: Node " + n.nodeId + ", entry " + i + " is null");
+ }
+
+ float nIncrease = n.mbr.enlargement(n.entries[i]);
+ float newNodeIncrease = newNode.mbr.enlargement(n.entries[i]);
+ float difference = Math.abs(nIncrease - newNodeIncrease);
+
+ if (difference > maxDifference) {
+ next = i;
+
+ if (nIncrease < newNodeIncrease) {
+ nextGroup = 0;
+ } else if (newNodeIncrease < nIncrease) {
+ nextGroup = 1;
+ } else if (n.mbr.area() < newNode.mbr.area()) {
+ nextGroup = 0;
+ } else if (newNode.mbr.area() < n.mbr.area()) {
+ nextGroup = 1;
+ } else if (newNode.entryCount < maxNodeEntries / 2) {
+ nextGroup = 0;
+ } else {
+ nextGroup = 1;
+ }
+ maxDifference = difference;
+ }
+ /*
+ if (log.isDebugEnabled()) {
+ log.debug("Entry " + i + " group0 increase = " + nIncrease + ", group1 increase = " + newNodeIncrease +
+ ", diff = " + difference + ", MaxDiff = " + maxDifference + " (entry " + next + ")");
+ }
+ */
+ }
+ }
+
+ entryStatus[next] = ENTRY_STATUS_ASSIGNED;
+
+ if (nextGroup == 0) {
+ n.mbr.add(n.entries[next]);
+ n.entryCount++;
+ } else {
+ // move to new node.
+ newNode.addEntryNoCopy(n.entries[next], n.ids[next]);
+ n.entries[next] = null;
+ }
+
+ return next;
+ }
+
+ /**
+ * Recursively searches the tree for the nearest entry. Other queries
+ * call execute() on an IntProcedure when a matching entry is found;
+ * however nearest() must store the entry Ids as it searches the tree,
+ * in case a nearer entry is found.
+ * Uses the member variable nearestIds to store the nearest
+ * entry IDs.
+ *
+ * [x] TODO rewrite this to be non-recursive?
+ */
+ private float nearest(Point p, Node n, float nearestDistance) {
+ for (int i = 0; i < n.entryCount; i++) {
+ float tempDistance = n.entries[i].distance(p);
+ if (n.isLeaf()) { // for leaves, the distance is an actual nearest distance
+ if (tempDistance < nearestDistance) {
+ nearestDistance = tempDistance;
+ nearestIds.clear();
+ }
+ if (tempDistance <= nearestDistance) {
+ nearestIds.add(n.ids[i]);
+ }
+ } else { // for index nodes, only go into them if they potentially could have
+ // a rectangle nearer than actualNearest
+ if (tempDistance <= nearestDistance) {
+ // search the child node
+ nearestDistance = nearest(p, getNode(n.ids[i]), nearestDistance);
+ }
+ }
+ }
+ return nearestDistance;
+ }
+
+ /**
+ * Recursively searches the tree for all intersecting entries.
+ * Immediately calls execute() on the passed IntProcedure when
+ * a matching entry is found.
+ *
+ * [x] TODO rewrite this to be non-recursive? Make sure it
+ * doesn't slow it down.
+ */
+ private void intersects(Rectangle r, IntProcedure v, Node n) {
+ for (int i = 0; i < n.entryCount; i++) {
+ if (r.intersects(n.entries[i])) {
+ if (n.isLeaf()) {
+ v.execute(n.ids[i]);
+ } else {
+ Node childNode = getNode(n.ids[i]);
+ intersects(r, v, childNode);
+ }
+ }
+ }
+ }
+
+ /**
+ * Used by delete(). Ensures that all nodes from the passed node
+ * up to the root have the minimum number of entries.
+ *
+ * Note that the parent and parentEntry stacks are expected to
+ * contain the nodeIds of all parents up to the root.
+ */
+ private Rectangle oldRectangle = new Rectangle(0, 0, 0, 0, 0, 0);
+ private void condenseTree(Node l) {
+ // CT1 [Initialize] Set n=l. Set the list of eliminated
+ // nodes to be empty.
+ Node n = l;
+ Node parent = null;
+ int parentEntry = 0;
+
+ TIntStack eliminatedNodeIds = new TIntStack();
+
+ // CT2 [Find parent entry] If N is the root, go to CT6. Otherwise
+ // let P be the parent of N, and let En be N's entry in P
+ while (n.level != treeHeight) {
+ parent = getNode(parents.pop());
+ parentEntry = parentsEntry.pop();
+
+ // CT3 [Eliminiate under-full node] If N has too few entries,
+ // delete En from P and add N to the list of eliminated nodes
+ if (n.entryCount < minNodeEntries) {
+ parent.deleteEntry(parentEntry, minNodeEntries);
+ eliminatedNodeIds.push(n.nodeId);
+ } else {
+ // CT4 [Adjust covering rectangle] If N has not been eliminated,
+ // adjust EnI to tightly contain all entries in N
+ if (!n.mbr.equals(parent.entries[parentEntry])) {
+ oldRectangle.set(parent.entries[parentEntry].min, parent.entries[parentEntry].max);
+ parent.entries[parentEntry].set(n.mbr.min, n.mbr.max);
+ parent.recalculateMBR(oldRectangle);
+ }
+ }
+ // CT5 [Move up one level in tree] Set N=P and repeat from CT2
+ n = parent;
+ }
+
+ // CT6 [Reinsert orphaned entries] Reinsert all entries of nodes in set Q.
+ // Entries from eliminated leaf nodes are reinserted in tree leaves as in
+ // Insert(), but entries from higher level nodes must be placed higher in
+ // the tree, so that leaves of their dependent subtrees will be on the same
+ // level as leaves of the main tree
+ while (eliminatedNodeIds.size() > 0) {
+ Node e = getNode(eliminatedNodeIds.pop());
+ for (int j = 0; j < e.entryCount; j++) {
+ add(e.entries[j], e.ids[j], e.level);
+ e.entries[j] = null;
+ }
+ e.entryCount = 0;
+ deletedNodeIds.push(e.nodeId);
+ }
+ }
+
+ /**
+ * Used by add(). Chooses a leaf to add the rectangle to.
+ */
+ private Node chooseNode(Rectangle r, int level) {
+ // CL1 [Initialize] Set N to be the root node
+ Node n = getNode(rootNodeId);
+ parents.clear();
+ parentsEntry.clear();
+
+ // CL2 [Leaf check] If N is a leaf, return N
+ while (true) {
+ if (n == null) {
+ throw new Error("Could not get root node (" + rootNodeId + ")");
+ }
+
+ if (n.level == level) {
+ return n;
+ }
+
+ // CL3 [Choose subtree] If N is not at the desired level, let F be the entry in N
+ // whose rectangle FI needs least enlargement to include EI. Resolve
+ // ties by choosing the entry with the rectangle of smaller area.
+ float leastEnlargement = n.getEntry(0).enlargement(r);
+ int index = 0; // index of rectangle in subtree
+ for (int i = 1; i < n.entryCount; i++) {
+ Rectangle tempRectangle = n.getEntry(i);
+ float tempEnlargement = tempRectangle.enlargement(r);
+ if ((tempEnlargement < leastEnlargement) ||
+ ((tempEnlargement == leastEnlargement) &&
+ (tempRectangle.area() < n.getEntry(index).area()))) {
+ index = i;
+ leastEnlargement = tempEnlargement;
+ }
+ }
+
+ parents.push(n.nodeId);
+ parentsEntry.push(index);
+
+ // CL4 [Descend until a leaf is reached] Set N to be the child node
+ // pointed to by Fp and repeat from CL2
+ n = getNode(n.ids[index]);
+ }
+ }
+
+ /**
+ * Ascend from a leaf node L to the root, adjusting covering rectangles and
+ * propagating node splits as necessary.
+ */
+ private Node adjustTree(Node n, Node nn) {
+ // AT1 [Initialize] Set N=L. If L was split previously, set NN to be
+ // the resulting second node.
+
+ // AT2 [Check if done] If N is the root, stop
+ while (n.level != treeHeight) {
+
+ // AT3 [Adjust covering rectangle in parent entry] Let P be the parent
+ // node of N, and let En be N's entry in P. Adjust EnI so that it tightly
+ // encloses all entry rectangles in N.
+ Node parent = getNode(parents.pop());
+ int entry = parentsEntry.pop();
+
+ if (parent.ids[entry] != n.nodeId) {
+ throw new Error("Error: entry " + entry + " in node " +
+ parent.nodeId + " should point to node " +
+ n.nodeId + "; actually points to node " + parent.ids[entry]);
+ }
+
+ if (!parent.entries[entry].equals(n.mbr)) {
+ parent.entries[entry].set(n.mbr.min, n.mbr.max);
+ parent.mbr.set(parent.entries[0].min, parent.entries[0].max);
+ for (int i = 1; i < parent.entryCount; i++) {
+ parent.mbr.add(parent.entries[i]);
+ }
+ }
+
+ // AT4 [Propagate node split upward] If N has a partner NN resulting from
+ // an earlier split, create a new entry Enn with Ennp pointing to NN and
+ // Enni enclosing all rectangles in NN. Add Enn to P if there is room.
+ // Otherwise, invoke splitNode to produce P and PP containing Enn and
+ // all P's old entries.
+ Node newNode = null;
+ if (nn != null) {
+ if (parent.entryCount < maxNodeEntries) {
+ parent.addEntry(nn.mbr, nn.nodeId);
+ } else {
+ newNode = splitNode(parent, nn.mbr.copy(), nn.nodeId);
+ }
+ }
+
+ // AT5 [Move up to next level] Set N = P and set NN = PP if a split
+ // occurred. Repeat from AT2
+ n = parent;
+ nn = newNode;
+
+ parent = null;
+ newNode = null;
+ }
+
+ return nn;
+ }
+
+ /**
+ * Check the consistency of the tree.
+ */
+ private void checkConsistency(int nodeId, int expectedLevel, Rectangle expectedMBR) {
+ // go through the tree, and check that the internal data structures of
+ // the tree are not corrupted.
+ Node n = getNode(nodeId);
+
+ if (n == null) {
+ throw new Error("Error: Could not read node " + nodeId);
+ }
+
+ if (n.level != expectedLevel) {
+ throw new Error("Error: Node " + nodeId + ", expected level " + expectedLevel + ", actual level " + n.level);
+ }
+
+ Rectangle calculatedMBR = calculateMBR(n);
+
+ if (!n.mbr.equals(calculatedMBR)) {
+ throw new Error("Error: Node " + nodeId + ", calculated MBR does not equal stored MBR");
+ }
+
+ if (expectedMBR != null && !n.mbr.equals(expectedMBR)) {
+ throw new Error("Error: Node " + nodeId + ", expected MBR (from parent) does not equal stored MBR");
+ }
+
+ // Check for corruption where a parent entry is the same object as the child MBR
+ if (expectedMBR != null && n.mbr.sameObject(expectedMBR)) {
+ throw new Error("Error: Node " + nodeId + " MBR using same rectangle object as parent's entry");
+ }
+
+ for (int i = 0; i < n.entryCount; i++) {
+ if (n.entries[i] == null) {
+ throw new Error("Error: Node " + nodeId + ", Entry " + i + " is null");
+ }
+
+ if (n.level > 1) { // if not a leaf
+ checkConsistency(n.ids[i], n.level - 1, n.entries[i]);
+ }
+ }
+ }
+
+ /**
+ * Given a node object, calculate the node MBR from it's entries.
+ * Used in consistency checking
+ */
+ private Rectangle calculateMBR(Node n) {
+ Rectangle mbr = new Rectangle(n.entries[0].min, n.entries[0].max);
+
+ for (int i = 1; i < n.entryCount; i++) {
+ mbr.add(n.entries[i]);
+ }
+ return mbr;
+ }
+}
projects / anneal.git / blobdiff