-What type should we infer for this?
- f x = (show ?y, x::Int)
-Since we must quantify over the ?y, the most plausible type is
- f :: (Show a, ?y::a) => Int -> (String, Int)
-But notice that the type of the RHS is (String,Int), with no type
-varibables mentioned at all! The type of f looks ambiguous. But
-it isn't, because at a call site we might have
- let ?y = 5::Int in f 7
+Only a *class* predicate can give rise to ambiguity
+An *implicit parameter* cannot. For example:
+ foo :: (?x :: [a]) => Int
+ foo = length ?x
+is fine. The call site will suppply a particular 'x'
+
+Furthermore, the type variables fixed by an implicit parameter
+propagate to the others. E.g.
+ foo :: (Show a, ?x::[a]) => Int
+ foo = show (?x++?x)
+The type of foo looks ambiguous. But it isn't, because at a call site
+we might have
+ let ?x = 5::Int in foo