Remove UseGcc makefile var

It couldn't be overridden, and was defined as YES.

diff --git a/mk/config.mk.in b/mk/config.mk.in
index e6126f6..4d93905 100644 (file)
--- a/mk/config.mk.in
+++ b/mk/config.mk.in
@@ -540,15 +540,10 @@ endif
 # the flag --with-gcc=<blah> instead.  The reason is that the configure script
 # needs to know which gcc you're using in order to perform its tests.
 
 # the flag --with-gcc=<blah> instead.  The reason is that the configure script
 # needs to know which gcc you're using in order to perform its tests.
 

-UseGcc         = YES

 WhatGccIsCalled = @WhatGccIsCalled@
 GccVersion      = @GccVersion@
 WhatGccIsCalled = @WhatGccIsCalled@
 GccVersion      = @GccVersion@

-GccLT34                = @GccLT34@
-ifneq "$(strip $(UseGcc))"  "YES"
-  CC   = cc
-else
-  CC   = $(WhatGccIsCalled)
-endif
+GccLT34         = @GccLT34@
+CC              = $(WhatGccIsCalled)

 
 # C compiler and linker flags from configure (e.g. -m<blah> to select
 # correct C compiler backend). The stage number is the stage of GHC
 
 # C compiler and linker flags from configure (e.g. -m<blah> to select
 # correct C compiler backend). The stage number is the stage of GHC